OSDev.org

What is your favorite power of 2?

The power of magic.

.5

-i

I usually think about the bit pattern.
Let's just say 128.

iansjack wrote:-i

Wouldn't that be 1?

m12 wrote:Wouldn't that be 1?

Only if i was zero and then you don't need the minus sign

I thought you meant i as in √(-1). the square root of √1 is 1, so logically -√(-1) = √1 = 1

You can't just multiply by negative 1 to covert complex-real numbers

2 to the power of -i is most definitely not 1! (And -i is most definitely not 1 either.)

Why not? 0 + i and 0 - i are valid complex numbers.

By the way, how about 2^e

pi-th root of 2 (2^(1/pi))

I'm sure there will be some of you who get the reference

m12 wrote:I thought you meant i as in √(-1). the square root of √1 is 1, so logically -√(-1) = √1 = 1

This is one of the most frequent problems with understanding complex numbers. i IS NOT sqrt(-1). This is NOT its definition. x = sqrt(-1) is NOT i.

i is defined as follows:

i^2 = -1

No other definition of i is correct, and all of them create the bullshit you wrote before, when you said -i = 1. -i is conceptually the same as (0, -1) in R2, which is *completely different thing* than 1, which is, again conceptually, (1, 0) in R2.


Please educate yourself on such basic things before diving into talking about it.

Hi,

Griwes wrote:i^2 = -1

No other definition of i is correct

i^6 = -1?

Cheers,
Adam

That ain't a definition. You used the fact that i^2 is -1, which is *the* definition, and you just used that fact to write (i^2)^3 = -1, which is the same as (-1)^3 = -1.